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sir1 (standard SIR)

$\displaystyle \frac{dS}{dt}$ $\displaystyle =-r S(t) I(t)$    
$\displaystyle \frac{dI}{dt}$ $\displaystyle =r S(t) I(t)-a I(t)$    
$\displaystyle \frac{dR}{dt}$ $\displaystyle =a I(t)$    

Figure 4.8: $ S$, $ I$ and $ R$
\includegraphics[scale=1]{images/sir1.eps}


Nicolas Bacaer 2004-06-18